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$\begingroup$ There is a reason why I like to define my autocorrelation function a little differently in the code I use for pitch detection. I don't like them ramps either. $\endgroup$
– robert bristow-johnson
Commented yesterday
2

$\begingroup$ Oh and Dan, of course if you wanna use the FFT and iFFT to do autocorrelation, you can get the same result as the MATLAB xcorr() by zero-padding $x[n]$ with as many zeros as input samples. Then the circular convolution will look just like linear convolution with the rectangularly-windowed input and you'll get the diamond shape. Of course that diamond envelope is deterministic and you can divide by it (someone did in some paper, but I can't remember who). It wouldn't even have to be a rectangular window. You could Hann window it and the envelope would look like the autocorrelation of Hann. $\endgroup$
– robert bristow-johnson
Commented yesterday
1

$\begingroup$ @robertbristow-johnson nice — yes I typically do the circular (don’t like the ramps) but perhaps it’s also because of the kind of waveforms I work with. Thanks $\endgroup$
– Dan Boschen
Commented yesterday
1

$\begingroup$ ..chat gods are soon going to yell at us for this long thread. - - - - - Yeah, you met Peter. He's the cat that keeps us lil' miceys in line. $\endgroup$
– robert bristow-johnson
Commented 12 hours ago
1

$\begingroup$ But I think I get it. You have a constellation of spread spectrum basis symbols. You wanna know how flat the are and how decorrelated they are. And I can see doing that with circular convolution. $\endgroup$
– robert bristow-johnson
Commented 12 hours ago

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